3(y^2+4)=20y

Solution for 3(y^2+4)=20y equation:

Simplifying
3(y2 + 4) = 20y

Reorder the terms:
3(4 + y2) = 20y
(4 * 3 + y2 * 3) = 20y
(12 + 3y2) = 20y

Solving
12 + 3y2 = 20y

Solving for variable 'y'.

Reorder the terms:
12 + -20y + 3y2 = 20y + -20y

Combine like terms: 20y + -20y = 0
12 + -20y + 3y2 = 0

Factor a trinomial.
(2 + -3y)(6 + -1y) = 0

Subproblem 1
Set the factor '(2 + -3y)' equal to zero and attempt to solve:

Simplifying
2 + -3y = 0

Solving
2 + -3y = 0

Move all terms containing y to the left, all other terms to the right.

Add '-2' to each side of the equation.
2 + -2 + -3y = 0 + -2

Combine like terms: 2 + -2 = 0
0 + -3y = 0 + -2
-3y = 0 + -2

Combine like terms: 0 + -2 = -2
-3y = -2

Divide each side by '-3'.
y = 0.6666666667

Simplifying
y = 0.6666666667
Subproblem 2
Set the factor '(6 + -1y)' equal to zero and attempt to solve:

Simplifying
6 + -1y = 0

Solving
6 + -1y = 0

Move all terms containing y to the left, all other terms to the right.

Add '-6' to each side of the equation.
6 + -6 + -1y = 0 + -6

Combine like terms: 6 + -6 = 0
0 + -1y = 0 + -6
-1y = 0 + -6

Combine like terms: 0 + -6 = -6
-1y = -6

Divide each side by '-1'.
y = 6

Simplifying
y = 6
Solution
y = {0.6666666667, 6}